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8z^2-6=378
We move all terms to the left:
8z^2-6-(378)=0
We add all the numbers together, and all the variables
8z^2-384=0
a = 8; b = 0; c = -384;
Δ = b2-4ac
Δ = 02-4·8·(-384)
Δ = 12288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12288}=\sqrt{4096*3}=\sqrt{4096}*\sqrt{3}=64\sqrt{3}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{3}}{2*8}=\frac{0-64\sqrt{3}}{16} =-\frac{64\sqrt{3}}{16} =-4\sqrt{3} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{3}}{2*8}=\frac{0+64\sqrt{3}}{16} =\frac{64\sqrt{3}}{16} =4\sqrt{3} $
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